Sr Examen

Expresión сv(¬b)v(a&¬c)v(b&¬a)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    c∨(¬b)∨(a∧(¬c))∨(b∧(¬a))
    $$c \vee \left(a \wedge \neg c\right) \vee \left(b \wedge \neg a\right) \vee \neg b$$
    Solución detallada
    $$c \vee \left(a \wedge \neg c\right) \vee \left(b \wedge \neg a\right) \vee \neg b = 1$$
    Simplificación [src]
    1
    1
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNCD [src]
    1
    1
    FND [src]
    Ya está reducido a FND
    1
    1
    FNC [src]
    Ya está reducido a FNC
    1
    1
    FNDP [src]
    1
    1