Expresión ¬(¬(a^b)->¬(b^¬c))->¬(¬(c^¬d)->¬(¬c^d))
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Solución
Solución detallada
$$\neg \left(a \wedge b\right) = \neg a \vee \neg b$$
$$\neg \left(b \wedge \neg c\right) = c \vee \neg b$$
$$\neg \left(a \wedge b\right) \Rightarrow \neg \left(b \wedge \neg c\right) = a \vee c \vee \neg b$$
$$\neg \left(a \wedge b\right) \not\Rightarrow \neg \left(b \wedge \neg c\right) = b \wedge \neg a \wedge \neg c$$
$$\neg \left(c \wedge \neg d\right) = d \vee \neg c$$
$$\neg \left(d \wedge \neg c\right) = c \vee \neg d$$
$$\neg \left(c \wedge \neg d\right) \Rightarrow \neg \left(d \wedge \neg c\right) = c \vee \neg d$$
$$\neg \left(c \wedge \neg d\right) \not\Rightarrow \neg \left(d \wedge \neg c\right) = d \wedge \neg c$$
$$\neg \left(a \wedge b\right) \not\Rightarrow \neg \left(b \wedge \neg c\right) \Rightarrow \neg \left(c \wedge \neg d\right) \not\Rightarrow \neg \left(d \wedge \neg c\right) = a \vee c \vee d \vee \neg b$$
$$a \vee c \vee d \vee \neg b$$
Tabla de verdad
+---+---+---+---+--------+
| a | b | c | d | result |
+===+===+===+===+========+
| 0 | 0 | 0 | 0 | 1 |
+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 1 |
+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 1 |
+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 1 |
+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 1 |
+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 1 |
+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 1 |
+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 1 |
+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 1 |
+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 1 |
+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 1 |
+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 1 |
+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 1 |
+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 1 |
+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 1 |
+---+---+---+---+--------+
Ya está reducido a FNC
$$a \vee c \vee d \vee \neg b$$
Ya está reducido a FND
$$a \vee c \vee d \vee \neg b$$
$$a \vee c \vee d \vee \neg b$$
$$a \vee c \vee d \vee \neg b$$