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Expresión ((¬a∨b)∧с)∨(a∧¬b∧c)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (a∧c∧(¬b))∨(c∧(b∨(¬a)))
    $$\left(c \wedge \left(b \vee \neg a\right)\right) \vee \left(a \wedge c \wedge \neg b\right)$$
    Solución detallada
    $$\left(c \wedge \left(b \vee \neg a\right)\right) \vee \left(a \wedge c \wedge \neg b\right) = c$$
    Simplificación [src]
    $$c$$
    c
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNDP [src]
    $$c$$
    c
    FND [src]
    Ya está reducido a FND
    $$c$$
    c
    FNCD [src]
    $$c$$
    c
    FNC [src]
    Ya está reducido a FNC
    $$c$$
    c