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Lógica matemática/ BD+B(D+E)+D(D+F)

Expresión BD+B(D+E)+D(D+F)

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    Solución

    Ha introducido [src] 
    (b∧d)∨(b∧(d∨e))∨(d∧(d∨f))
    $$\left(b \wedge d\right) \vee \left(b \wedge \left(d \vee e\right)\right) \vee \left(d \wedge \left(d \vee f\right)\right)$$
    Solución detallada
    $$d \wedge \left(d \vee f\right) = d$$
    $$\left(b \wedge d\right) \vee \left(b \wedge \left(d \vee e\right)\right) \vee \left(d \wedge \left(d \vee f\right)\right) = d \vee \left(b \wedge e\right)$$
    Simplificación [src]
    $$d \vee \left(b \wedge e\right)$$ 
    d∨(b∧e)
    Tabla de verdad 
    +---+---+---+---+--------+
| b | d | e | f | result |
+===+===+===+===+========+
| 0 | 0 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 1      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 1      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 1      |
+---+---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    $$d \vee \left(b \wedge e\right)$$ 
    d∨(b∧e)
    FNC [src]
    $$\left(b \vee d\right) \wedge \left(d \vee e\right)$$ 
    (b∨d)∧(d∨e)
    FNCD [src]
    $$\left(b \vee d\right) \wedge \left(d \vee e\right)$$ 
    (b∨d)∧(d∨e)
    FNDP [src]
    $$d \vee \left(b \wedge e\right)$$ 
    d∨(b∧e)
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