Sr Examen

Expresión Неp*неx+неp*a+неa*неx

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (a∧(¬p))∨((¬a)∧(¬x))∨((¬p)∧(¬x))
    $$\left(a \wedge \neg p\right) \vee \left(\neg a \wedge \neg x\right) \vee \left(\neg p \wedge \neg x\right)$$
    Solución detallada
    $$\left(a \wedge \neg p\right) \vee \left(\neg a \wedge \neg x\right) \vee \left(\neg p \wedge \neg x\right) = \left(a \wedge \neg p\right) \vee \left(\neg a \wedge \neg x\right)$$
    Simplificación [src]
    $$\left(a \wedge \neg p\right) \vee \left(\neg a \wedge \neg x\right)$$
    (a∧(¬p))∨((¬a)∧(¬x))
    Tabla de verdad
    +---+---+---+--------+
    | a | p | x | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 0      |
    +---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    $$\left(a \wedge \neg p\right) \vee \left(\neg a \wedge \neg x\right)$$
    (a∧(¬p))∨((¬a)∧(¬x))
    FNDP [src]
    $$\left(a \wedge \neg p\right) \vee \left(\neg a \wedge \neg x\right)$$
    (a∧(¬p))∨((¬a)∧(¬x))
    FNCD [src]
    $$\left(a \vee \neg x\right) \wedge \left(\neg a \vee \neg p\right)$$
    (a∨(¬x))∧((¬a)∨(¬p))
    FNC [src]
    $$\left(a \vee \neg a\right) \wedge \left(a \vee \neg x\right) \wedge \left(\neg a \vee \neg p\right) \wedge \left(\neg p \vee \neg x\right)$$
    (a∨(¬a))∧(a∨(¬x))∧((¬a)∨(¬p))∧((¬p)∨(¬x))