Sr Examen
Expresión с∧b∧(¬a∧b)∧(¬bva)va∧b
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Solución
Ha introducido
[src]
(a∧b)∨(b∧c∧(¬a)∧(a∨(¬b)))
$$\left(a \wedge b\right) \vee \left(b \wedge c \wedge \neg a \wedge \left(a \vee \neg b\right)\right)$$
Solución detallada
$$b \wedge c \wedge \neg a \wedge \left(a \vee \neg b\right) = \text{False}$$
$$\left(a \wedge b\right) \vee \left(b \wedge c \wedge \neg a \wedge \left(a \vee \neg b\right)\right) = a \wedge b$$
$$\left(a \wedge b\right) \vee \left(b \wedge c \wedge \neg a \wedge \left(a \vee \neg b\right)\right) = a \wedge b$$
Tabla de verdad
+---+---+---+--------+ | a | b | c | result | +===+===+===+========+ | 0 | 0 | 0 | 0 | +---+---+---+--------+ | 0 | 0 | 1 | 0 | +---+---+---+--------+ | 0 | 1 | 0 | 0 | +---+---+---+--------+ | 0 | 1 | 1 | 0 | +---+---+---+--------+ | 1 | 0 | 0 | 0 | +---+---+---+--------+ | 1 | 0 | 1 | 0 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+