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Expresión ¬a∨(¬b∧c)∧b

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (¬a)∨(b∧c∧(¬b))
    $$\left(b \wedge c \wedge \neg b\right) \vee \neg a$$
    Solución detallada
    $$b \wedge c \wedge \neg b = \text{False}$$
    $$\left(b \wedge c \wedge \neg b\right) \vee \neg a = \neg a$$
    Simplificación [src]
    $$\neg a$$
    ¬a
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 0      |
    +---+---+---+--------+
    FNDP [src]
    $$\neg a$$
    ¬a
    FNC [src]
    Ya está reducido a FNC
    $$\neg a$$
    ¬a
    FNCD [src]
    $$\neg a$$
    ¬a
    FND [src]
    Ya está reducido a FND
    $$\neg a$$
    ¬a