Expresión (¬z∧¬y)(z∨(¬y∧x))∨(z∨y)(¬z∧(y∨¬x))
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$\neg z \wedge \left(y \vee z\right) \wedge \left(y \vee \neg x\right) = y \wedge \neg z$$
$$\neg y \wedge \neg z \wedge \left(z \vee \left(x \wedge \neg y\right)\right) = x \wedge \neg y \wedge \neg z$$
$$\left(\neg y \wedge \neg z \wedge \left(z \vee \left(x \wedge \neg y\right)\right)\right) \vee \left(\neg z \wedge \left(y \vee z\right) \wedge \left(y \vee \neg x\right)\right) = \neg z \wedge \left(x \vee y\right)$$
$$\neg z \wedge \left(x \vee y\right)$$
Tabla de verdad
+---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 1 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 0 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 0 |
+---+---+---+--------+
$$\left(x \wedge \neg z\right) \vee \left(y \wedge \neg z\right)$$
Ya está reducido a FNC
$$\neg z \wedge \left(x \vee y\right)$$
$$\neg z \wedge \left(x \vee y\right)$$
$$\left(x \wedge \neg z\right) \vee \left(y \wedge \neg z\right)$$