Sr Examen
Expresión AvB&C⇒¬(A&B&C)
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
(a∨(b∧c))⇒(¬(a∧b∧c))
$$\left(a \vee \left(b \wedge c\right)\right) \Rightarrow \neg \left(a \wedge b \wedge c\right)$$
Solución detallada
$$\neg \left(a \wedge b \wedge c\right) = \neg a \vee \neg b \vee \neg c$$
$$\left(a \vee \left(b \wedge c\right)\right) \Rightarrow \neg \left(a \wedge b \wedge c\right) = \neg a \vee \neg b \vee \neg c$$
$$\left(a \vee \left(b \wedge c\right)\right) \Rightarrow \neg \left(a \wedge b \wedge c\right) = \neg a \vee \neg b \vee \neg c$$
Tabla de verdad
+---+---+---+--------+ | a | b | c | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 1 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 0 | +---+---+---+--------+