Sr Examen

Expresión (P∨(Q∨R))∨(((P∧Q)∧R)∧P)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    p∨q∨r∨(p∧q∧r)
    $$p \vee q \vee r \vee \left(p \wedge q \wedge r\right)$$
    Solución detallada
    $$p \vee q \vee r \vee \left(p \wedge q \wedge r\right) = p \vee q \vee r$$
    Simplificación [src]
    $$p \vee q \vee r$$
    p∨q∨r
    Tabla de verdad
    +---+---+---+--------+
    | p | q | r | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNDP [src]
    $$p \vee q \vee r$$
    p∨q∨r
    FNC [src]
    Ya está reducido a FNC
    $$p \vee q \vee r$$
    p∨q∨r
    FNCD [src]
    $$p \vee q \vee r$$
    p∨q∨r
    FND [src]
    Ya está reducido a FND
    $$p \vee q \vee r$$
    p∨q∨r