Expresión cv(a⇔b)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
$$a ⇔ b = \left(a \wedge b\right) \vee \left(\neg a \wedge \neg b\right)$$
$$c \vee \left(a ⇔ b\right) = c \vee \left(a \wedge b\right) \vee \left(\neg a \wedge \neg b\right)$$
$$c \vee \left(a \wedge b\right) \vee \left(\neg a \wedge \neg b\right)$$
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 1 |
+---+---+---+--------+
| 0 | 0 | 1 | 1 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
Ya está reducido a FND
$$c \vee \left(a \wedge b\right) \vee \left(\neg a \wedge \neg b\right)$$
$$\left(a \vee c \vee \neg a\right) \wedge \left(a \vee c \vee \neg b\right) \wedge \left(b \vee c \vee \neg a\right) \wedge \left(b \vee c \vee \neg b\right)$$
(a∨c∨(¬a))∧(a∨c∨(¬b))∧(b∨c∨(¬a))∧(b∨c∨(¬b))
$$c \vee \left(a \wedge b\right) \vee \left(\neg a \wedge \neg b\right)$$
$$\left(a \vee c \vee \neg b\right) \wedge \left(b \vee c \vee \neg a\right)$$