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Lógica matemática/ notbandcandnotdornotbandnotcandnotd

Expresión notbandcandnotdornotbandnotcandnotd

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    Solución

    Ha introducido [src] 
    (c∧(¬b)∧(¬d))∨((¬b)∧(¬c)∧(¬d))
    $$\left(c \wedge \neg b \wedge \neg d\right) \vee \left(\neg b \wedge \neg c \wedge \neg d\right)$$
    Solución detallada
    $$\left(c \wedge \neg b \wedge \neg d\right) \vee \left(\neg b \wedge \neg c \wedge \neg d\right) = \neg b \wedge \neg d$$
    Simplificación [src]
    $$\neg b \wedge \neg d$$ 
    (¬b)∧(¬d)
    Tabla de verdad 
    +---+---+---+--------+
| b | c | d | result |
+===+===+===+========+
| 0 | 0 | 0 | 1      |
+---+---+---+--------+
| 0 | 0 | 1 | 0      |
+---+---+---+--------+
| 0 | 1 | 0 | 1      |
+---+---+---+--------+
| 0 | 1 | 1 | 0      |
+---+---+---+--------+
| 1 | 0 | 0 | 0      |
+---+---+---+--------+
| 1 | 0 | 1 | 0      |
+---+---+---+--------+
| 1 | 1 | 0 | 0      |
+---+---+---+--------+
| 1 | 1 | 1 | 0      |
+---+---+---+--------+
    FNDP [src]
    $$\neg b \wedge \neg d$$ 
    (¬b)∧(¬d)
    FNCD [src]
    $$\neg b \wedge \neg d$$ 
    (¬b)∧(¬d)
    FNC [src]
    Ya está reducido a FNC
    $$\neg b \wedge \neg d$$ 
    (¬b)∧(¬d)
    FND [src]
    Ya está reducido a FND
    $$\neg b \wedge \neg d$$ 
    (¬b)∧(¬d)
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