Sr Examen
Lógica matemática/ bcornot(bc)anda

Expresión bcornot(bc)anda

El profesor se sorprenderá mucho al ver tu solución correcta😉

⌨

    Solución

    Ha introducido [src] 
    (b∧c)∨(a∧(¬(b∧c)))
    $$\left(a \wedge \neg \left(b \wedge c\right)\right) \vee \left(b \wedge c\right)$$
    Solución detallada
    $$\neg \left(b \wedge c\right) = \neg b \vee \neg c$$
    $$a \wedge \neg \left(b \wedge c\right) = a \wedge \left(\neg b \vee \neg c\right)$$
    $$\left(a \wedge \neg \left(b \wedge c\right)\right) \vee \left(b \wedge c\right) = a \vee \left(b \wedge c\right)$$
    Simplificación [src]
    $$a \vee \left(b \wedge c\right)$$ 
    a∨(b∧c)
    Tabla de verdad 
    +---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 0      |
+---+---+---+--------+
| 0 | 1 | 0 | 0      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 1      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 1      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    $$a \vee \left(b \wedge c\right)$$ 
    a∨(b∧c)
    FNDP [src]
    $$a \vee \left(b \wedge c\right)$$ 
    a∨(b∧c)
    FNCD [src]
    $$\left(a \vee b\right) \wedge \left(a \vee c\right)$$ 
    (a∨b)∧(a∨c)
    FNC [src]
    $$\left(a \vee b\right) \wedge \left(a \vee c\right)$$ 
    (a∨b)∧(a∨c)
    © Sr Examen – Калькулятор