Sr Examen

Expresión x(-z)vy(-z)vy

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    y∨(x∧(¬z))∨(y∧(¬z))
    $$y \vee \left(x \wedge \neg z\right) \vee \left(y \wedge \neg z\right)$$
    Solución detallada
    $$y \vee \left(x \wedge \neg z\right) \vee \left(y \wedge \neg z\right) = y \vee \left(x \wedge \neg z\right)$$
    Simplificación [src]
    $$y \vee \left(x \wedge \neg z\right)$$
    y∨(x∧(¬z))
    Tabla de verdad
    +---+---+---+--------+
    | x | y | z | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNDP [src]
    $$y \vee \left(x \wedge \neg z\right)$$
    y∨(x∧(¬z))
    FND [src]
    Ya está reducido a FND
    $$y \vee \left(x \wedge \neg z\right)$$
    y∨(x∧(¬z))
    FNCD [src]
    $$\left(x \vee y\right) \wedge \left(y \vee \neg z\right)$$
    (x∨y)∧(y∨(¬z))
    FNC [src]
    $$\left(x \vee y\right) \wedge \left(y \vee \neg z\right)$$
    (x∨y)∧(y∨(¬z))