Sr Examen

Expresión not(¬((a→b)and(b→a))and¬c)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    ¬((¬c)∧(¬((a⇒b)∧(b⇒a))))
    $$\neg \left(\neg c \wedge \neg \left(\left(a \Rightarrow b\right) \wedge \left(b \Rightarrow a\right)\right)\right)$$
    Solución detallada
    $$a \Rightarrow b = b \vee \neg a$$
    $$b \Rightarrow a = a \vee \neg b$$
    $$\left(a \Rightarrow b\right) \wedge \left(b \Rightarrow a\right) = \left(a \wedge b\right) \vee \left(\neg a \wedge \neg b\right)$$
    $$\neg \left(\left(a \Rightarrow b\right) \wedge \left(b \Rightarrow a\right)\right) = \left(a \wedge \neg b\right) \vee \left(b \wedge \neg a\right)$$
    $$\neg c \wedge \neg \left(\left(a \Rightarrow b\right) \wedge \left(b \Rightarrow a\right)\right) = \neg c \wedge \left(a \vee b\right) \wedge \left(\neg a \vee \neg b\right)$$
    $$\neg \left(\neg c \wedge \neg \left(\left(a \Rightarrow b\right) \wedge \left(b \Rightarrow a\right)\right)\right) = c \vee \left(a \wedge b\right) \vee \left(\neg a \wedge \neg b\right)$$
    Simplificación [src]
    $$c \vee \left(a \wedge b\right) \vee \left(\neg a \wedge \neg b\right)$$
    c∨(a∧b)∨((¬a)∧(¬b))
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNCD [src]
    $$\left(a \vee c \vee \neg b\right) \wedge \left(b \vee c \vee \neg a\right)$$
    (a∨c∨(¬b))∧(b∨c∨(¬a))
    FNC [src]
    $$\left(a \vee c \vee \neg a\right) \wedge \left(a \vee c \vee \neg b\right) \wedge \left(b \vee c \vee \neg a\right) \wedge \left(b \vee c \vee \neg b\right)$$
    (a∨c∨(¬a))∧(a∨c∨(¬b))∧(b∨c∨(¬a))∧(b∨c∨(¬b))
    FND [src]
    Ya está reducido a FND
    $$c \vee \left(a \wedge b\right) \vee \left(\neg a \wedge \neg b\right)$$
    c∨(a∧b)∨((¬a)∧(¬b))
    FNDP [src]
    $$c \vee \left(a \wedge b\right) \vee \left(\neg a \wedge \neg b\right)$$
    c∨(a∧b)∨((¬a)∧(¬b))