Sr Examen

Expresión неB×(A+C)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (¬b)∧(a∨c)
    $$\neg b \wedge \left(a \vee c\right)$$
    Simplificación [src]
    $$\neg b \wedge \left(a \vee c\right)$$
    (¬b)∧(a∨c)
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 0      |
    +---+---+---+--------+
    FNC [src]
    Ya está reducido a FNC
    $$\neg b \wedge \left(a \vee c\right)$$
    (¬b)∧(a∨c)
    FND [src]
    $$\left(a \wedge \neg b\right) \vee \left(c \wedge \neg b\right)$$
    (a∧(¬b))∨(c∧(¬b))
    FNDP [src]
    $$\left(a \wedge \neg b\right) \vee \left(c \wedge \neg b\right)$$
    (a∧(¬b))∨(c∧(¬b))
    FNCD [src]
    $$\neg b \wedge \left(a \vee c\right)$$
    (¬b)∧(a∨c)