Sr Examen
Lógica matemática/ x(-z)by(-z)

Expresión x(-z)by(-z)

El profesor se sorprenderá mucho al ver tu solución correcta😉

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    Solución

    Ha introducido [src] 
    b∧x∧y∧(¬z)
    $$b \wedge x \wedge y \wedge \neg z$$
    Simplificación [src]
    $$b \wedge x \wedge y \wedge \neg z$$ 
    b∧x∧y∧(¬z)
    Tabla de verdad 
    +---+---+---+---+--------+
| b | x | y | z | result |
+===+===+===+===+========+
| 0 | 0 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 0      |
+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 0      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 1      |
+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 0      |
+---+---+---+---+--------+
    FNDP [src]
    $$b \wedge x \wedge y \wedge \neg z$$ 
    b∧x∧y∧(¬z)
    FNCD [src]
    $$b \wedge x \wedge y \wedge \neg z$$ 
    b∧x∧y∧(¬z)
    FNC [src]
    Ya está reducido a FNC
    $$b \wedge x \wedge y \wedge \neg z$$ 
    b∧x∧y∧(¬z)
    FND [src]
    Ya está reducido a FND
    $$b \wedge x \wedge y \wedge \neg z$$ 
    b∧x∧y∧(¬z)
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