Sr Examen
Expresión cv(¬av¬b&¬c)&(¬a&¬bv¬c)
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Solución
Ha introducido
[src]
c∨(((¬a)∨((¬b)∧(¬c)))∧((¬c)∨((¬a)∧(¬b))))
$$c \vee \left(\left(\left(\neg b \wedge \neg c\right) \vee \neg a\right) \wedge \left(\left(\neg a \wedge \neg b\right) \vee \neg c\right)\right)$$
Solución detallada
$$\left(\left(\neg b \wedge \neg c\right) \vee \neg a\right) \wedge \left(\left(\neg a \wedge \neg b\right) \vee \neg c\right) = \left(\neg a \wedge \neg b\right) \vee \left(\neg a \wedge \neg c\right) \vee \left(\neg b \wedge \neg c\right)$$
$$c \vee \left(\left(\left(\neg b \wedge \neg c\right) \vee \neg a\right) \wedge \left(\left(\neg a \wedge \neg b\right) \vee \neg c\right)\right) = c \vee \neg a \vee \neg b$$
$$c \vee \left(\left(\left(\neg b \wedge \neg c\right) \vee \neg a\right) \wedge \left(\left(\neg a \wedge \neg b\right) \vee \neg c\right)\right) = c \vee \neg a \vee \neg b$$
Tabla de verdad
+---+---+---+--------+ | a | b | c | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 1 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 0 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+