Sr Examen
Lógica matemática/ с&(!a∨b)∨(c∨(!a&b))

Expresión с&(!a∨b)∨(c∨(!a&b))

El profesor se sorprenderá mucho al ver tu solución correcta😉

⌨

    Solución

    Ha introducido [src] 
    c∨(b∧(¬a))∨(c∧(b∨(¬a)))
    $$c \vee \left(b \wedge \neg a\right) \vee \left(c \wedge \left(b \vee \neg a\right)\right)$$
    Solución detallada
    $$c \vee \left(b \wedge \neg a\right) \vee \left(c \wedge \left(b \vee \neg a\right)\right) = c \vee \left(b \wedge \neg a\right)$$
    Simplificación [src]
    $$c \vee \left(b \wedge \neg a\right)$$ 
    c∨(b∧(¬a))
    Tabla de verdad 
    +---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 1      |
+---+---+---+--------+
| 0 | 1 | 0 | 1      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 0      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 0      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FNDP [src]
    $$c \vee \left(b \wedge \neg a\right)$$ 
    c∨(b∧(¬a))
    FNC [src]
    $$\left(b \vee c\right) \wedge \left(c \vee \neg a\right)$$ 
    (b∨c)∧(c∨(¬a))
    FND [src]
    Ya está reducido a FND
    $$c \vee \left(b \wedge \neg a\right)$$ 
    c∨(b∧(¬a))
    FNCD [src]
    $$\left(b \vee c\right) \wedge \left(c \vee \neg a\right)$$ 
    (b∨c)∧(c∨(¬a))
    © Sr Examen