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Expresión (avb)&((¬a&¬bvc)v¬c)&(avb)

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (a∨b)∧(c∨(¬c)∨((¬a)∧(¬b)))
    $$\left(a \vee b\right) \wedge \left(c \vee \left(\neg a \wedge \neg b\right) \vee \neg c\right)$$
    Solución detallada
    $$c \vee \left(\neg a \wedge \neg b\right) \vee \neg c = 1$$
    $$\left(a \vee b\right) \wedge \left(c \vee \left(\neg a \wedge \neg b\right) \vee \neg c\right) = a \vee b$$
    Simplificación [src]
    $$a \vee b$$
    a∨b
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    $$a \vee b$$
    a∨b
    FNDP [src]
    $$a \vee b$$
    a∨b
    FNCD [src]
    $$a \vee b$$
    a∨b
    FNC [src]
    Ya está reducido a FNC
    $$a \vee b$$
    a∨b