Sr Examen
Expresión bdor((notdorc)and(aorc)and(notcora)and(notcornotd))or(notbandd)
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
(b∧d)∨(d∧(¬b))∨((a∨c)∧(a∨(¬c))∧(c∨(¬d))∧((¬c)∨(¬d)))
$$\left(b \wedge d\right) \vee \left(d \wedge \neg b\right) \vee \left(\left(a \vee c\right) \wedge \left(a \vee \neg c\right) \wedge \left(c \vee \neg d\right) \wedge \left(\neg c \vee \neg d\right)\right)$$
Solución detallada
$$\left(a \vee c\right) \wedge \left(a \vee \neg c\right) \wedge \left(c \vee \neg d\right) \wedge \left(\neg c \vee \neg d\right) = a \wedge \neg d$$
$$\left(b \wedge d\right) \vee \left(d \wedge \neg b\right) \vee \left(\left(a \vee c\right) \wedge \left(a \vee \neg c\right) \wedge \left(c \vee \neg d\right) \wedge \left(\neg c \vee \neg d\right)\right) = a \vee d$$
$$\left(b \wedge d\right) \vee \left(d \wedge \neg b\right) \vee \left(\left(a \vee c\right) \wedge \left(a \vee \neg c\right) \wedge \left(c \vee \neg d\right) \wedge \left(\neg c \vee \neg d\right)\right) = a \vee d$$
Tabla de verdad
+---+---+---+---+--------+ | a | b | c | d | result | +===+===+===+===+========+ | 0 | 0 | 0 | 0 | 0 | +---+---+---+---+--------+ | 0 | 0 | 0 | 1 | 1 | +---+---+---+---+--------+ | 0 | 0 | 1 | 0 | 0 | +---+---+---+---+--------+ | 0 | 0 | 1 | 1 | 1 | +---+---+---+---+--------+ | 0 | 1 | 0 | 0 | 0 | +---+---+---+---+--------+ | 0 | 1 | 0 | 1 | 1 | +---+---+---+---+--------+ | 0 | 1 | 1 | 0 | 0 | +---+---+---+---+--------+ | 0 | 1 | 1 | 1 | 1 | +---+---+---+---+--------+ | 1 | 0 | 0 | 0 | 1 | +---+---+---+---+--------+ | 1 | 0 | 0 | 1 | 1 | +---+---+---+---+--------+ | 1 | 0 | 1 | 0 | 1 | +---+---+---+---+--------+ | 1 | 0 | 1 | 1 | 1 | +---+---+---+---+--------+ | 1 | 1 | 0 | 0 | 1 | +---+---+---+---+--------+ | 1 | 1 | 0 | 1 | 1 | +---+---+---+---+--------+ | 1 | 1 | 1 | 0 | 1 | +---+---+---+---+--------+ | 1 | 1 | 1 | 1 | 1 | +---+---+---+---+--------+