Sr Examen
xy=40; x^lgy=4
Solución
Ha introducido
[src]
x*y = 40
$$x y = 40$$
log(y) x = 4
$$x^{\log{\left(y \right)}} = 4$$
x^log(y) = 4
Respuesta rápida
$$x_{1} = \frac{2 \sqrt{10}}{e^{\frac{\sqrt{- \log{\left(256 \right)} + \log{\left(40 \right)}^{2}}}{2}}}$$
=
$$\frac{2 \sqrt{10}}{e^{\frac{\sqrt{- \log{\left(256 \right)} + \log{\left(40 \right)}^{2}}}{2}}}$$
=
$$y_{1} = 2 \sqrt{10} e^{\frac{\sqrt{- \log{\left(256 \right)} + \log{\left(40 \right)}^{2}}}{2}}$$
=
$$2 \sqrt{10} e^{\frac{\sqrt{- \log{\left(256 \right)} + \log{\left(40 \right)}^{2}}}{2}}$$
=
=
$$\frac{2 \sqrt{10}}{e^{\frac{\sqrt{- \log{\left(256 \right)} + \log{\left(40 \right)}^{2}}}{2}}}$$
=
1.52913018263282
$$y_{1} = 2 \sqrt{10} e^{\frac{\sqrt{- \log{\left(256 \right)} + \log{\left(40 \right)}^{2}}}{2}}$$
=
$$2 \sqrt{10} e^{\frac{\sqrt{- \log{\left(256 \right)} + \log{\left(40 \right)}^{2}}}{2}}$$
=
26.1586622606120
$$x_{2} = 2 \sqrt{10} e^{\frac{\sqrt{- \log{\left(256 \right)} + \log{\left(40 \right)}^{2}}}{2}}$$
=
$$2 \sqrt{10} e^{\frac{\sqrt{- \log{\left(256 \right)} + \log{\left(40 \right)}^{2}}}{2}}$$
=
$$y_{2} = \frac{2 \sqrt{10}}{e^{\frac{\sqrt{- \log{\left(256 \right)} + \log{\left(40 \right)}^{2}}}{2}}}$$
=
$$\frac{2 \sqrt{10}}{e^{\frac{\sqrt{- \log{\left(256 \right)} + \log{\left(40 \right)}^{2}}}{2}}}$$
=
=
$$2 \sqrt{10} e^{\frac{\sqrt{- \log{\left(256 \right)} + \log{\left(40 \right)}^{2}}}{2}}$$
=
26.1586622606120
$$y_{2} = \frac{2 \sqrt{10}}{e^{\frac{\sqrt{- \log{\left(256 \right)} + \log{\left(40 \right)}^{2}}}{2}}}$$
=
$$\frac{2 \sqrt{10}}{e^{\frac{\sqrt{- \log{\left(256 \right)} + \log{\left(40 \right)}^{2}}}{2}}}$$
=
1.52913018263282