Sr Examen
sinx+siny=1; x+y=p/3
Solución
Ha introducido
[src]
sin(x) + sin(y) = 1
$$\sin{\left(x \right)} + \sin{\left(y \right)} = 1$$
p
x + y = -
3
$$x + y = \frac{p}{3}$$
x + y = p/3
Respuesta rápida
$$p_{1} = 3 y - 3 \operatorname{asin}{\left(\sin{\left(y \right)} - 1 \right)}$$
=
$$3 y - 3 \operatorname{asin}{\left(\sin{\left(y \right)} - 1 \right)}$$
=
$$x_{1} = - \operatorname{asin}{\left(\sin{\left(y \right)} - 1 \right)}$$
=
$$- \operatorname{asin}{\left(\sin{\left(y \right)} - 1 \right)}$$
=
=
$$3 y - 3 \operatorname{asin}{\left(\sin{\left(y \right)} - 1 \right)}$$
=
3*y - 3*asin(-1 + sin(y))
$$x_{1} = - \operatorname{asin}{\left(\sin{\left(y \right)} - 1 \right)}$$
=
$$- \operatorname{asin}{\left(\sin{\left(y \right)} - 1 \right)}$$
=
-asin(-1 + sin(y))
$$p_{2} = 3 y + 3 \operatorname{asin}{\left(\sin{\left(y \right)} - 1 \right)} + 3 \pi$$
=
$$3 y + 3 \operatorname{asin}{\left(\sin{\left(y \right)} - 1 \right)} + 3 \pi$$
=
$$x_{2} = \operatorname{asin}{\left(\sin{\left(y \right)} - 1 \right)} + \pi$$
=
$$\operatorname{asin}{\left(\sin{\left(y \right)} - 1 \right)} + \pi$$
=
=
$$3 y + 3 \operatorname{asin}{\left(\sin{\left(y \right)} - 1 \right)} + 3 \pi$$
=
9.42477796076938 + 3*y + 3*asin(-1 + sin(y))
$$x_{2} = \operatorname{asin}{\left(\sin{\left(y \right)} - 1 \right)} + \pi$$
=
$$\operatorname{asin}{\left(\sin{\left(y \right)} - 1 \right)} + \pi$$
=
3.14159265358979 + asin(-1 + sin(y))