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Solución de sistemas de ecuaciones/ xy=1; x+y=1

xy=1; x+y=1

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Solución

Ha introducido [src] 
x*y = 1
xy=1x y = 1 
x + y = 1
x+y=1x + y = 1 
x + y = 1
Respuesta rápida
x1=12−3i2x_{1} = \frac{1}{2} - \frac{\sqrt{3} i}{2}
=
12−3i2\frac{1}{2} - \frac{\sqrt{3} i}{2}
=
0.5 - 0.866025403784439*i

y1=12+3i2y_{1} = \frac{1}{2} + \frac{\sqrt{3} i}{2}
=
12+3i2\frac{1}{2} + \frac{\sqrt{3} i}{2}
=
0.5 + 0.866025403784439*i
x2=12+3i2x_{2} = \frac{1}{2} + \frac{\sqrt{3} i}{2}
=
12+3i2\frac{1}{2} + \frac{\sqrt{3} i}{2}
=
0.5 + 0.866025403784439*i

y2=12−3i2y_{2} = \frac{1}{2} - \frac{\sqrt{3} i}{2}
=
12−3i2\frac{1}{2} - \frac{\sqrt{3} i}{2}
=
0.5 - 0.866025403784439*i
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