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xz=3; 1-y^2=2+x

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Solución

Ha introducido [src]
x*z = 3
$$x z = 3$$
     2        
1 - y  = 2 + x
$$1 - y^{2} = x + 2$$
1 - y^2 = x + 2
Respuesta rápida
$$x_{1} = \frac{3}{z}$$
=
$$\frac{3}{z}$$
=
3/z

$$y_{1} = - \sqrt{- \frac{z + 3}{z}}$$
=
$$- \sqrt{- \frac{z + 3}{z}}$$
=
-(-(3 + z)/z)^0.5
$$x_{2} = \frac{3}{z}$$
=
$$\frac{3}{z}$$
=
3/z

$$y_{2} = \sqrt{- \frac{z + 3}{z}}$$
=
$$\sqrt{\frac{- z - 3}{z}}$$
=
(-(3 + z)/z)^0.5