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Simplificamos:
Respuesta:
2*y + 1 / 2*y + 1 \ asin (3) |asin (3) 2*y + 1 | y *|-------------- + 2*asin (3)*log(y)*log(asin(3))| \ y /
1 + 2*y / 2 \ asin (3) |/1 \ 2 + 4*y 1 + 2*y / 1 4*log(asin(3)) 2 \| y *||- + 2*log(y)*log(asin(3))| *asin (3) + asin (3)*|- -- + -------------- + 4*log (asin(3))*log(y)|| |\y / | 2 y || \ \ y //
1 + 2*y / 3 / 2 \ \ asin (3) |/1 \ 3 + 6*y 1 + 2*y |1 3*log(asin(3)) 3 6*log (asin(3))| 2 + 4*y /1 \ / 1 4*log(asin(3)) 2 \| y *||- + 2*log(y)*log(asin(3))| *asin (3) + 2*asin (3)*|-- - -------------- + 4*log (asin(3))*log(y) + ---------------| + 3*asin (3)*|- + 2*log(y)*log(asin(3))|*|- -- + -------------- + 4*log (asin(3))*log(y)|| |\y / | 3 2 y | \y / | 2 y || \ \y y / \ y //