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Ecuación diferencial ((x)^4lnx-2xy^3)dx+3x^2y^2dy=0

El profesor se sorprenderá mucho al ver tu solución correcta😉

v

Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
 4               3         2  2    d           
x *log(x) - 2*x*y (x) + 3*x *y (x)*--(y(x)) = 0
                                   dx          
$$x^{4} \log{\left(x \right)} + 3 x^{2} y^{2}{\left(x \right)} \frac{d}{d x} y{\left(x \right)} - 2 x y^{3}{\left(x \right)} = 0$$
x^4*log(x) + 3*x^2*y^2*y' - 2*x*y^3 = 0
Respuesta [src]
          ________________________               
       3 /  2                      /         ___\
       \/  x *(C1 + x - x*log(x)) *\-1 - I*\/ 3 /
y(x) = ------------------------------------------
                           2                     
$$y{\left(x \right)} = \frac{\sqrt[3]{x^{2} \left(C_{1} - x \log{\left(x \right)} + x\right)} \left(-1 - \sqrt{3} i\right)}{2}$$
          ________________________               
       3 /  2                      /         ___\
       \/  x *(C1 + x - x*log(x)) *\-1 + I*\/ 3 /
y(x) = ------------------------------------------
                           2                     
$$y{\left(x \right)} = \frac{\sqrt[3]{x^{2} \left(C_{1} - x \log{\left(x \right)} + x\right)} \left(-1 + \sqrt{3} i\right)}{2}$$
          ________________________
       3 /  2                     
y(x) = \/  x *(C1 + x - x*log(x)) 
$$y{\left(x \right)} = \sqrt[3]{x^{2} \left(C_{1} - x \log{\left(x \right)} + x\right)}$$
Gráfico para el problema de Cauchy
Clasificación
factorable
1st exact
almost linear
lie group
1st exact Integral
almost linear Integral
Respuesta numérica [src]
(x, y):
(-10.0, 0.75)
(-7.777777777777778, nan)
(-5.555555555555555, nan)
(-3.333333333333333, nan)
(-1.1111111111111107, nan)
(1.1111111111111107, nan)
(3.333333333333334, nan)
(5.555555555555557, nan)
(7.777777777777779, nan)
(10.0, nan)
(10.0, nan)