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Ecuación diferencial y''-2y'+5y=25x^2+12

El profesor se sorprenderá mucho al ver tu solución correcta😉

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Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

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Solución

Ha introducido [src]
                          2                   
    d                    d                   2
- 2*--(y(x)) + 5*y(x) + ---(y(x)) = 12 + 25*x 
    dx                    2                   
                        dx                    
$$5 y{\left(x \right)} - 2 \frac{d}{d x} y{\left(x \right)} + \frac{d^{2}}{d x^{2}} y{\left(x \right)} = 25 x^{2} + 12$$
5*y - 2*y' + y'' = 25*x^2 + 12
Respuesta [src]
                    2                                x
y(x) = 2 + 4*x + 5*x  + (C1*sin(2*x) + C2*cos(2*x))*e 
$$y{\left(x \right)} = 5 x^{2} + 4 x + \left(C_{1} \sin{\left(2 x \right)} + C_{2} \cos{\left(2 x \right)}\right) e^{x} + 2$$
Clasificación
nth linear constant coeff undetermined coefficients
nth linear constant coeff variation of parameters
nth linear constant coeff variation of parameters Integral