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f(x-2)=40 la ecuación

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Solución numérica:

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Solución

Ha introducido [src] 
f*(x - 2) = 40
f(x−2)=40f \left(x - 2\right) = 40
Simplificar
Gráfica
Respuesta rápida [src] 
             40*re(f)         40*I*im(f)  
x1 = 2 + --------------- - ---------------
           2        2        2        2   
         im (f) + re (f)   im (f) + re (f)
x1=2+40re⁡(f)(re⁡(f))2+(im⁡(f))2−40iim⁡(f)(re⁡(f))2+(im⁡(f))2x_{1} = 2 + \frac{40 \operatorname{re}{\left(f\right)}}{\left(\operatorname{re}{\left(f\right)}\right)^{2} + \left(\operatorname{im}{\left(f\right)}\right)^{2}} - \frac{40 i \operatorname{im}{\left(f\right)}}{\left(\operatorname{re}{\left(f\right)}\right)^{2} + \left(\operatorname{im}{\left(f\right)}\right)^{2}} 
x1 = 2 + 40*re(f)/(re(f)^2 + im(f)^2) - 40*i*im(f)/(re(f)^2 + im(f)^2)
Suma y producto de raíces [src] 
suma
        40*re(f)         40*I*im(f)  
2 + --------------- - ---------------
      2        2        2        2   
    im (f) + re (f)   im (f) + re (f)
2+40re⁡(f)(re⁡(f))2+(im⁡(f))2−40iim⁡(f)(re⁡(f))2+(im⁡(f))22 + \frac{40 \operatorname{re}{\left(f\right)}}{\left(\operatorname{re}{\left(f\right)}\right)^{2} + \left(\operatorname{im}{\left(f\right)}\right)^{2}} - \frac{40 i \operatorname{im}{\left(f\right)}}{\left(\operatorname{re}{\left(f\right)}\right)^{2} + \left(\operatorname{im}{\left(f\right)}\right)^{2}} 
=
        40*re(f)         40*I*im(f)  
2 + --------------- - ---------------
      2        2        2        2   
    im (f) + re (f)   im (f) + re (f)
2+40re⁡(f)(re⁡(f))2+(im⁡(f))2−40iim⁡(f)(re⁡(f))2+(im⁡(f))22 + \frac{40 \operatorname{re}{\left(f\right)}}{\left(\operatorname{re}{\left(f\right)}\right)^{2} + \left(\operatorname{im}{\left(f\right)}\right)^{2}} - \frac{40 i \operatorname{im}{\left(f\right)}}{\left(\operatorname{re}{\left(f\right)}\right)^{2} + \left(\operatorname{im}{\left(f\right)}\right)^{2}} 
producto
        40*re(f)         40*I*im(f)  
2 + --------------- - ---------------
      2        2        2        2   
    im (f) + re (f)   im (f) + re (f)
2+40re⁡(f)(re⁡(f))2+(im⁡(f))2−40iim⁡(f)(re⁡(f))2+(im⁡(f))22 + \frac{40 \operatorname{re}{\left(f\right)}}{\left(\operatorname{re}{\left(f\right)}\right)^{2} + \left(\operatorname{im}{\left(f\right)}\right)^{2}} - \frac{40 i \operatorname{im}{\left(f\right)}}{\left(\operatorname{re}{\left(f\right)}\right)^{2} + \left(\operatorname{im}{\left(f\right)}\right)^{2}} 
=
  /  2        2                           \
2*\im (f) + re (f) + 20*re(f) - 20*I*im(f)/
-------------------------------------------
                2        2                 
              im (f) + re (f)
2((re⁡(f))2+20re⁡(f)+(im⁡(f))2−20iim⁡(f))(re⁡(f))2+(im⁡(f))2\frac{2 \left(\left(\operatorname{re}{\left(f\right)}\right)^{2} + 20 \operatorname{re}{\left(f\right)} + \left(\operatorname{im}{\left(f\right)}\right)^{2} - 20 i \operatorname{im}{\left(f\right)}\right)}{\left(\operatorname{re}{\left(f\right)}\right)^{2} + \left(\operatorname{im}{\left(f\right)}\right)^{2}} 
2*(im(f)^2 + re(f)^2 + 20*re(f) - 20*i*im(f))/(im(f)^2 + re(f)^2)
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