El profesor se sorprenderá mucho al ver tu solución correcta😉
2 2 (x - 1) + 2*(y - 2) = 1
a*x^2 + b*x + c = 0
D = b^2 - 4 * a * c =
(-2)^2 - 4 * (1) * (8 - 8*y + 2*y^2) = -28 - 8*y^2 + 32*y
x1 = (-b + sqrt(D)) / (2*a)
x2 = (-b - sqrt(D)) / (2*a)
____________________________________________________________________ ____________________________________________________________________ / 2 / / 2 2 \\ / 2 / / 2 2 \\ 4 / 2 / 2 2 \ |atan2\8*im(y) - 4*im(y)*re(y), -7 - 2*re (y) + 2*im (y) + 8*re(y)/| 4 / 2 / 2 2 \ |atan2\8*im(y) - 4*im(y)*re(y), -7 - 2*re (y) + 2*im (y) + 8*re(y)/| x1 = 1 - \/ (8*im(y) - 4*im(y)*re(y)) + \-7 - 2*re (y) + 2*im (y) + 8*re(y)/ *cos|------------------------------------------------------------------| - I*\/ (8*im(y) - 4*im(y)*re(y)) + \-7 - 2*re (y) + 2*im (y) + 8*re(y)/ *sin|------------------------------------------------------------------| \ 2 / \ 2 /
____________________________________________________________________ ____________________________________________________________________ / 2 / / 2 2 \\ / 2 / / 2 2 \\ 4 / 2 / 2 2 \ |atan2\8*im(y) - 4*im(y)*re(y), -7 - 2*re (y) + 2*im (y) + 8*re(y)/| 4 / 2 / 2 2 \ |atan2\8*im(y) - 4*im(y)*re(y), -7 - 2*re (y) + 2*im (y) + 8*re(y)/| x2 = 1 + \/ (8*im(y) - 4*im(y)*re(y)) + \-7 - 2*re (y) + 2*im (y) + 8*re(y)/ *cos|------------------------------------------------------------------| + I*\/ (8*im(y) - 4*im(y)*re(y)) + \-7 - 2*re (y) + 2*im (y) + 8*re(y)/ *sin|------------------------------------------------------------------| \ 2 / \ 2 /
x2 = i*((-4*re(y)*im(y) + 8*im(y))^2 + (-2*re(y)^2 + 8*re(y) + 2*im(y)^2 - 7)^2)^(1/4)*sin(atan2(-4*re(y)*im(y) + 8*im(y, -2*re(y)^2 + 8*re(y) + 2*im(y)^2 - 7)/2) + ((-4*re(y)*im(y) + 8*im(y))^2 + (-2*re(y)^2 + 8*re(y) + 2*im(y)^2 - 7)^2)^(1/4)*cos(atan2(-4*re(y)*im(y) + 8*im(y), -2*re(y)^2 + 8*re(y) + 2*im(y)^2 - 7)/2) + 1)