El profesor se sorprenderá mucho al ver tu solución correcta😉
a*b^2 + b*b + c = 0
D = b^2 - 4 * a * c =
(-3*a)^2 - 4 * (-1) * (a^2) = 13*a^2
b1 = (-b + sqrt(D)) / (2*a)
b2 = (-b - sqrt(D)) / (2*a)
/ ____\ / ____\ | 3 \/ 13 | | 3 \/ 13 | b1 = |- - + ------|*re(a) + I*|- - + ------|*im(a) \ 2 2 / \ 2 2 /
/ ____\ / ____\ | 3 \/ 13 | | 3 \/ 13 | b2 = |- - - ------|*re(a) + I*|- - - ------|*im(a) \ 2 2 / \ 2 2 /
b2 = (-sqrt(13)/2 - 3/2)*re(a) + i*(-sqrt(13)/2 - 3/2)*im(a)
suma
/ ____\ / ____\ / ____\ / ____\ | 3 \/ 13 | | 3 \/ 13 | | 3 \/ 13 | | 3 \/ 13 | |- - + ------|*re(a) + I*|- - + ------|*im(a) + |- - - ------|*re(a) + I*|- - - ------|*im(a) \ 2 2 / \ 2 2 / \ 2 2 / \ 2 2 /
=
/ ____\ / ____\ / ____\ / ____\ | 3 \/ 13 | | 3 \/ 13 | | 3 \/ 13 | | 3 \/ 13 | |- - + ------|*re(a) + |- - - ------|*re(a) + I*|- - + ------|*im(a) + I*|- - - ------|*im(a) \ 2 2 / \ 2 2 / \ 2 2 / \ 2 2 /
producto
// ____\ / ____\ \ // ____\ / ____\ \ || 3 \/ 13 | | 3 \/ 13 | | || 3 \/ 13 | | 3 \/ 13 | | ||- - + ------|*re(a) + I*|- - + ------|*im(a)|*||- - - ------|*re(a) + I*|- - - ------|*im(a)| \\ 2 2 / \ 2 2 / / \\ 2 2 / \ 2 2 / /
=
2 2 im (a) - re (a) - 2*I*im(a)*re(a)
im(a)^2 - re(a)^2 - 2*i*im(a)*re(a)