y(1-x-y^2)=0 la ecuación
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
2 2
x1 = 1 + im (y) - re (y) - 2*I*im(y)*re(y)
$$x_{1} = - \left(\operatorname{re}{\left(y\right)}\right)^{2} - 2 i \operatorname{re}{\left(y\right)} \operatorname{im}{\left(y\right)} + \left(\operatorname{im}{\left(y\right)}\right)^{2} + 1$$
x1 = -re(y)^2 - 2*i*re(y)*im(y) + im(y)^2 + 1
Suma y producto de raíces
[src]
2 2
1 + im (y) - re (y) - 2*I*im(y)*re(y)
$$- \left(\operatorname{re}{\left(y\right)}\right)^{2} - 2 i \operatorname{re}{\left(y\right)} \operatorname{im}{\left(y\right)} + \left(\operatorname{im}{\left(y\right)}\right)^{2} + 1$$
2 2
1 + im (y) - re (y) - 2*I*im(y)*re(y)
$$- \left(\operatorname{re}{\left(y\right)}\right)^{2} - 2 i \operatorname{re}{\left(y\right)} \operatorname{im}{\left(y\right)} + \left(\operatorname{im}{\left(y\right)}\right)^{2} + 1$$
2 2
1 + im (y) - re (y) - 2*I*im(y)*re(y)
$$- \left(\operatorname{re}{\left(y\right)}\right)^{2} - 2 i \operatorname{re}{\left(y\right)} \operatorname{im}{\left(y\right)} + \left(\operatorname{im}{\left(y\right)}\right)^{2} + 1$$
2 2
1 + im (y) - re (y) - 2*I*im(y)*re(y)
$$- \left(\operatorname{re}{\left(y\right)}\right)^{2} - 2 i \operatorname{re}{\left(y\right)} \operatorname{im}{\left(y\right)} + \left(\operatorname{im}{\left(y\right)}\right)^{2} + 1$$
1 + im(y)^2 - re(y)^2 - 2*i*im(y)*re(y)