Sr Examen
Expresión ((¬pvq)&(r&p))v(qv¬r)
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
q∨(¬r)∨(p∧r∧(q∨(¬p)))
$$q \vee \left(p \wedge r \wedge \left(q \vee \neg p\right)\right) \vee \neg r$$
Solución detallada
$$p \wedge r \wedge \left(q \vee \neg p\right) = p \wedge q \wedge r$$
$$q \vee \left(p \wedge r \wedge \left(q \vee \neg p\right)\right) \vee \neg r = q \vee \neg r$$
$$q \vee \left(p \wedge r \wedge \left(q \vee \neg p\right)\right) \vee \neg r = q \vee \neg r$$
Tabla de verdad
+---+---+---+--------+ | p | q | r | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 0 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 0 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+