Sr Examen
Expresión сv¬bva&¬cvb&¬a
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Solución
Ha introducido
[src]
c∨(¬b)∨(a∧(¬c))∨(b∧(¬a))
$$c \vee \left(a \wedge \neg c\right) \vee \left(b \wedge \neg a\right) \vee \neg b$$
Solución detallada
$$c \vee \left(a \wedge \neg c\right) \vee \left(b \wedge \neg a\right) \vee \neg b = 1$$
Tabla de verdad
+---+---+---+--------+ | a | b | c | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 1 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 1 | +---+---+---+--------+ | 1 | 0 | 1 | 1 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+