Sr Examen
Expresión ab+bc+¬a¬b¬c
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
(a∧b)∨(b∧c)∨((¬a)∧(¬b)∧(¬c))
$$\left(a \wedge b\right) \vee \left(b \wedge c\right) \vee \left(\neg a \wedge \neg b \wedge \neg c\right)$$
Simplificación
[src]
$$\left(a \wedge b\right) \vee \left(b \wedge c\right) \vee \left(\neg a \wedge \neg b \wedge \neg c\right)$$
(a∧b)∨(b∧c)∨((¬a)∧(¬b)∧(¬c))
Tabla de verdad
+---+---+---+--------+ | a | b | c | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 0 | +---+---+---+--------+ | 0 | 1 | 0 | 0 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 0 | +---+---+---+--------+ | 1 | 0 | 1 | 0 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 1 | +---+---+---+--------+
FNDP
[src]
$$\left(a \wedge b\right) \vee \left(b \wedge c\right) \vee \left(\neg a \wedge \neg b \wedge \neg c\right)$$
(a∧b)∨(b∧c)∨((¬a)∧(¬b)∧(¬c))
FNC
[src]
$$\left(b \vee \neg a\right) \wedge \left(b \vee \neg b\right) \wedge \left(b \vee \neg c\right) \wedge \left(a \vee b \vee \neg a\right) \wedge \left(a \vee b \vee \neg b\right) \wedge \left(a \vee b \vee \neg c\right) \wedge \left(a \vee c \vee \neg a\right) \wedge \left(a \vee c \vee \neg b\right) \wedge \left(a \vee c \vee \neg c\right) \wedge \left(b \vee c \vee \neg a\right) \wedge \left(b \vee c \vee \neg b\right) \wedge \left(b \vee c \vee \neg c\right)$$
(b∨(¬a))∧(b∨(¬b))∧(b∨(¬c))∧(a∨b∨(¬a))∧(a∨b∨(¬b))∧(a∨b∨(¬c))∧(a∨c∨(¬a))∧(a∨c∨(¬b))∧(a∨c∨(¬c))∧(b∨c∨(¬a))∧(b∨c∨(¬b))∧(b∨c∨(¬c))
FND
[src]
Ya está reducido a FND
$$\left(a \wedge b\right) \vee \left(b \wedge c\right) \vee \left(\neg a \wedge \neg b \wedge \neg c\right)$$
(a∧b)∨(b∧c)∨((¬a)∧(¬b)∧(¬c))
FNCD
[src]
$$\left(b \vee \neg a\right) \wedge \left(b \vee \neg c\right) \wedge \left(a \vee c \vee \neg b\right)$$
(b∨(¬a))∧(b∨(¬c))∧(a∨c∨(¬b))