Sr Examen

Expresión ab!c+ad+!ab+ac!d

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (a∧b)∨(a∧d)∨(a∧b∧(¬c))∨(a∧c∧(¬d))
    (ab)(ad)(ab¬c)(ac¬d)\left(a \wedge b\right) \vee \left(a \wedge d\right) \vee \left(a \wedge b \wedge \neg c\right) \vee \left(a \wedge c \wedge \neg d\right)
    Solución detallada
    (ab)(ad)(ab¬c)(ac¬d)=a(bcd)\left(a \wedge b\right) \vee \left(a \wedge d\right) \vee \left(a \wedge b \wedge \neg c\right) \vee \left(a \wedge c \wedge \neg d\right) = a \wedge \left(b \vee c \vee d\right)
    Simplificación [src]
    a(bcd)a \wedge \left(b \vee c \vee d\right)
    a∧(b∨c∨d)
    Tabla de verdad
    +---+---+---+---+--------+
    | a | b | c | d | result |
    +===+===+===+===+========+
    | 0 | 0 | 0 | 0 | 0      |
    +---+---+---+---+--------+
    | 0 | 0 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 0 | 0      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 1 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 0 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 0 | 0      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 1 | 0      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 0 | 0      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    FNC [src]
    Ya está reducido a FNC
    a(bcd)a \wedge \left(b \vee c \vee d\right)
    a∧(b∨c∨d)
    FND [src]
    (ab)(ac)(ad)\left(a \wedge b\right) \vee \left(a \wedge c\right) \vee \left(a \wedge d\right)
    (a∧b)∨(a∧c)∨(a∧d)
    FNDP [src]
    (ab)(ac)(ad)\left(a \wedge b\right) \vee \left(a \wedge c\right) \vee \left(a \wedge d\right)
    (a∧b)∨(a∧c)∨(a∧d)
    FNCD [src]
    a(bcd)a \wedge \left(b \vee c \vee d\right)
    a∧(b∨c∨d)