Sr Examen

Expresión AC∨BC∨AC

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    Solución

    Ha introducido [src]
    (a∧c)∨(b∧c)
    (ac)(bc)\left(a \wedge c\right) \vee \left(b \wedge c\right)
    Solución detallada
    (ac)(bc)=c(ab)\left(a \wedge c\right) \vee \left(b \wedge c\right) = c \wedge \left(a \vee b\right)
    Simplificación [src]
    c(ab)c \wedge \left(a \vee b\right)
    c∧(a∨b)
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNC [src]
    Ya está reducido a FNC
    c(ab)c \wedge \left(a \vee b\right)
    c∧(a∨b)
    FNDP [src]
    (ac)(bc)\left(a \wedge c\right) \vee \left(b \wedge c\right)
    (a∧c)∨(b∧c)
    FNCD [src]
    c(ab)c \wedge \left(a \vee b\right)
    c∧(a∨b)
    FND [src]
    (ac)(bc)\left(a \wedge c\right) \vee \left(b \wedge c\right)
    (a∧c)∨(b∧c)