Expresión AC∨BC∨AC
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
(a∧c)∨(b∧c)=c∧(a∨b)
c∧(a∨b)
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 0 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
Ya está reducido a FNC
c∧(a∨b)
(a∧c)∨(b∧c)
c∧(a∨b)
(a∧c)∨(b∧c)