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Lógica matemática/ x∨y→x∨zx∨y→x∨z

Expresión x∨y→x∨zx∨y→x∨z

El profesor se sorprenderá mucho al ver tu solución correcta😉

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    Solución

    Ha introducido [src] 
    ((x∨y)⇒(x∨y∨(x∧z)))⇒(x∨z)
    ((x∨y)⇒(x∨y∨(x∧z)))⇒(x∨z)\left(\left(x \vee y\right) \Rightarrow \left(x \vee y \vee \left(x \wedge z\right)\right)\right) \Rightarrow \left(x \vee z\right)
    Solución detallada
    x∨y∨(x∧z)=x∨yx \vee y \vee \left(x \wedge z\right) = x \vee y
    (x∨y)⇒(x∨y∨(x∧z))=1\left(x \vee y\right) \Rightarrow \left(x \vee y \vee \left(x \wedge z\right)\right) = 1
    ((x∨y)⇒(x∨y∨(x∧z)))⇒(x∨z)=x∨z\left(\left(x \vee y\right) \Rightarrow \left(x \vee y \vee \left(x \wedge z\right)\right)\right) \Rightarrow \left(x \vee z\right) = x \vee z
    Simplificación [src]
    x∨zx \vee z 
    x∨z
    Tabla de verdad 
    +---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 1      |
+---+---+---+--------+
| 0 | 1 | 0 | 0      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 1      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 1      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    x∨zx \vee z 
    x∨z
    FNDP [src]
    x∨zx \vee z 
    x∨z
    FNCD [src]
    x∨zx \vee z 
    x∨z
    FNC [src]
    Ya está reducido a FNC
    x∨zx \vee z 
    x∨z
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