Expresión (AvB)&(AvBvC)&(AvC)&(BvC)
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
(a∨b)∧(a∨c)∧(b∨c)∧(a∨b∨c)=(a∧b)∨(a∧c)∨(b∧c)
(a∧b)∨(a∧c)∨(b∧c)
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 1 |
+---+---+---+--------+
| 1 | 0 | 0 | 0 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
Ya está reducido a FND
(a∧b)∨(a∧c)∨(b∧c)
(a∨b)∧(a∨c)∧(b∨c)
(a∧b)∨(a∧c)∨(b∧c)
(a∨b)∧(a∨c)∧(b∨c)∧(a∨b∨c)
(a∨b)∧(a∨c)∧(b∨c)∧(a∨b∨c)