Expresión bcdorabcornotaandnotbanddornotaanddandnotc
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
(a∧b∧c)∨(b∧c∧d)∨(d∧¬a∧¬b)∨(d∧¬a∧¬c)=(a∨d)∧(b∨¬a)∧(c∨¬a)
(a∨d)∧(b∨¬a)∧(c∨¬a)
Tabla de verdad
+---+---+---+---+--------+
| a | b | c | d | result |
+===+===+===+===+========+
| 0 | 0 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 0 | 0 | 0 | 1 | 1 |
+---+---+---+---+--------+
| 0 | 0 | 1 | 0 | 0 |
+---+---+---+---+--------+
| 0 | 0 | 1 | 1 | 1 |
+---+---+---+---+--------+
| 0 | 1 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 0 | 1 | 0 | 1 | 1 |
+---+---+---+---+--------+
| 0 | 1 | 1 | 0 | 0 |
+---+---+---+---+--------+
| 0 | 1 | 1 | 1 | 1 |
+---+---+---+---+--------+
| 1 | 0 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 0 | 0 | 1 | 0 |
+---+---+---+---+--------+
| 1 | 0 | 1 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 0 | 1 | 1 | 0 |
+---+---+---+---+--------+
| 1 | 1 | 0 | 0 | 0 |
+---+---+---+---+--------+
| 1 | 1 | 0 | 1 | 0 |
+---+---+---+---+--------+
| 1 | 1 | 1 | 0 | 1 |
+---+---+---+---+--------+
| 1 | 1 | 1 | 1 | 1 |
+---+---+---+---+--------+
(a∨d)∧(b∨¬a)∧(c∨¬a)
(d∧¬a)∨(a∧b∧c)
Ya está reducido a FNC
(a∨d)∧(b∨¬a)∧(c∨¬a)
(a∧¬a)∨(d∧¬a)∨(a∧b∧c)∨(a∧b∧¬a)∨(a∧c∧¬a)∨(b∧c∧d)∨(b∧d∧¬a)∨(c∧d∧¬a)
(a∧(¬a))∨(d∧(¬a))∨(a∧b∧c)∨(b∧c∧d)∨(a∧b∧(¬a))∨(a∧c∧(¬a))∨(b∧d∧(¬a))∨(c∧d∧(¬a))