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Expresión ¬x∨(y*z)⇒¬(z*w)∨y

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    ((¬x)∨(y∧z))⇒(y∨(¬(w∧z)))
    $$\left(\left(y \wedge z\right) \vee \neg x\right) \Rightarrow \left(y \vee \neg \left(w \wedge z\right)\right)$$
    Solución detallada
    $$\neg \left(w \wedge z\right) = \neg w \vee \neg z$$
    $$y \vee \neg \left(w \wedge z\right) = y \vee \neg w \vee \neg z$$
    $$\left(\left(y \wedge z\right) \vee \neg x\right) \Rightarrow \left(y \vee \neg \left(w \wedge z\right)\right) = x \vee y \vee \neg w \vee \neg z$$
    Simplificación [src]
    $$x \vee y \vee \neg w \vee \neg z$$
    x∨y∨(¬w)∨(¬z)
    Tabla de verdad
    +---+---+---+---+--------+
    | w | x | y | z | result |
    +===+===+===+===+========+
    | 0 | 0 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 0 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 0 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 0 | 1 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 0 | 1 | 0      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 0 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 0 | 1 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 0 | 1      |
    +---+---+---+---+--------+
    | 1 | 1 | 1 | 1 | 1      |
    +---+---+---+---+--------+
    FNC [src]
    Ya está reducido a FNC
    $$x \vee y \vee \neg w \vee \neg z$$
    x∨y∨(¬w)∨(¬z)
    FND [src]
    Ya está reducido a FND
    $$x \vee y \vee \neg w \vee \neg z$$
    x∨y∨(¬w)∨(¬z)
    FNDP [src]
    $$x \vee y \vee \neg w \vee \neg z$$
    x∨y∨(¬w)∨(¬z)
    FNCD [src]
    $$x \vee y \vee \neg w \vee \neg z$$
    x∨y∨(¬w)∨(¬z)