Sr Examen

Expresión ¬a∧¬b∧¬c∨¬a∧¬b∧c∨a∧¬b∧¬c∨a∧b∧c

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    (a∧b∧c)∨(a∧(¬b)∧(¬c))∨(c∧(¬a)∧(¬b))∨((¬a)∧(¬b)∧(¬c))
    $$\left(a \wedge b \wedge c\right) \vee \left(a \wedge \neg b \wedge \neg c\right) \vee \left(c \wedge \neg a \wedge \neg b\right) \vee \left(\neg a \wedge \neg b \wedge \neg c\right)$$
    Solución detallada
    $$\left(a \wedge b \wedge c\right) \vee \left(a \wedge \neg b \wedge \neg c\right) \vee \left(c \wedge \neg a \wedge \neg b\right) \vee \left(\neg a \wedge \neg b \wedge \neg c\right) = \left(\neg a \wedge \neg b\right) \vee \left(\neg b \wedge \neg c\right) \vee \left(a \wedge b \wedge c\right)$$
    Simplificación [src]
    $$\left(\neg a \wedge \neg b\right) \vee \left(\neg b \wedge \neg c\right) \vee \left(a \wedge b \wedge c\right)$$
    (a∧b∧c)∨((¬a)∧(¬b))∨((¬b)∧(¬c))
    Tabla de verdad
    +---+---+---+--------+
    | a | b | c | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FNCD [src]
    $$\left(a \vee \neg b\right) \wedge \left(c \vee \neg b\right) \wedge \left(b \vee \neg a \vee \neg c\right)$$
    (a∨(¬b))∧(c∨(¬b))∧(b∨(¬a)∨(¬c))
    FNDP [src]
    $$\left(\neg a \wedge \neg b\right) \vee \left(\neg b \wedge \neg c\right) \vee \left(a \wedge b \wedge c\right)$$
    (a∧b∧c)∨((¬a)∧(¬b))∨((¬b)∧(¬c))
    FNC [src]
    $$\left(a \vee \neg b\right) \wedge \left(b \vee \neg b\right) \wedge \left(c \vee \neg b\right) \wedge \left(a \vee \neg a \vee \neg b\right) \wedge \left(a \vee \neg a \vee \neg c\right) \wedge \left(a \vee \neg b \vee \neg c\right) \wedge \left(b \vee \neg a \vee \neg b\right) \wedge \left(b \vee \neg a \vee \neg c\right) \wedge \left(b \vee \neg b \vee \neg c\right) \wedge \left(c \vee \neg a \vee \neg b\right) \wedge \left(c \vee \neg a \vee \neg c\right) \wedge \left(c \vee \neg b \vee \neg c\right)$$
    (a∨(¬b))∧(b∨(¬b))∧(c∨(¬b))∧(a∨(¬a)∨(¬b))∧(a∨(¬a)∨(¬c))∧(a∨(¬b)∨(¬c))∧(b∨(¬a)∨(¬b))∧(b∨(¬a)∨(¬c))∧(b∨(¬b)∨(¬c))∧(c∨(¬a)∨(¬b))∧(c∨(¬a)∨(¬c))∧(c∨(¬b)∨(¬c))
    FND [src]
    Ya está reducido a FND
    $$\left(\neg a \wedge \neg b\right) \vee \left(\neg b \wedge \neg c\right) \vee \left(a \wedge b \wedge c\right)$$
    (a∧b∧c)∨((¬a)∧(¬b))∨((¬b)∧(¬c))