Sr Examen
Expresión ¬(P∧(Q→R))
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Solución detallada
$$q \Rightarrow r = r \vee \neg q$$
$$p \wedge \left(q \Rightarrow r\right) = p \wedge \left(r \vee \neg q\right)$$
$$\neg \left(p \wedge \left(q \Rightarrow r\right)\right) = \left(q \wedge \neg r\right) \vee \neg p$$
$$p \wedge \left(q \Rightarrow r\right) = p \wedge \left(r \vee \neg q\right)$$
$$\neg \left(p \wedge \left(q \Rightarrow r\right)\right) = \left(q \wedge \neg r\right) \vee \neg p$$
Tabla de verdad
+---+---+---+--------+ | p | q | r | result | +===+===+===+========+ | 0 | 0 | 0 | 1 | +---+---+---+--------+ | 0 | 0 | 1 | 1 | +---+---+---+--------+ | 0 | 1 | 0 | 1 | +---+---+---+--------+ | 0 | 1 | 1 | 1 | +---+---+---+--------+ | 1 | 0 | 0 | 0 | +---+---+---+--------+ | 1 | 0 | 1 | 0 | +---+---+---+--------+ | 1 | 1 | 0 | 1 | +---+---+---+--------+ | 1 | 1 | 1 | 0 | +---+---+---+--------+
FNCD
[src]
$$\left(q \vee \neg p\right) \wedge \left(\neg p \vee \neg r\right)$$
(q∨(¬p))∧((¬p)∨(¬r))
FNC
[src]
$$\left(q \vee \neg p\right) \wedge \left(\neg p \vee \neg r\right)$$
(q∨(¬p))∧((¬p)∨(¬r))