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Lógica matemática/ А•((B+C)+B•C)+A

Expresión А•((B+C)+B•C)+A

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    Solución

    Ha introducido [src] 
    a∨(a∧(b∨c∨(b∧c)))
    a∨(a∧(b∨c∨(b∧c)))a \vee \left(a \wedge \left(b \vee c \vee \left(b \wedge c\right)\right)\right)
    Solución detallada
    b∨c∨(b∧c)=b∨cb \vee c \vee \left(b \wedge c\right) = b \vee c
    a∧(b∨c∨(b∧c))=a∧(b∨c)a \wedge \left(b \vee c \vee \left(b \wedge c\right)\right) = a \wedge \left(b \vee c\right)
    a∨(a∧(b∨c∨(b∧c)))=aa \vee \left(a \wedge \left(b \vee c \vee \left(b \wedge c\right)\right)\right) = a
    Simplificación [src]
    aa 
    a
    Tabla de verdad 
    +---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 0      |
+---+---+---+--------+
| 0 | 1 | 0 | 0      |
+---+---+---+--------+
| 0 | 1 | 1 | 0      |
+---+---+---+--------+
| 1 | 0 | 0 | 1      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 1      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FNC [src]
    Ya está reducido a FNC
    aa 
    a
    FNDP [src]
    aa 
    a
    FND [src]
    Ya está reducido a FND
    aa 
    a
    FNCD [src]
    aa 
    a
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