Expresión А¬B+В¬C+АС
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
(a∧c)∨(a∧¬b)∨(b∧¬c)=a∨(b∧¬c)
a∨(b∧¬c)
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 1 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
(a∨b)∧(a∨¬c)
(a∨b)∧(a∨¬c)
a∨(b∧¬c)
Ya está reducido a FND
a∨(b∧¬c)