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Lógica matemática/ bVc=>a

Expresión bVc=>a

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    Solución

    Ha introducido [src] 
    (b∨c)⇒a
    $$\left(b \vee c\right) \Rightarrow a$$
    Solución detallada
    $$\left(b \vee c\right) \Rightarrow a = a \vee \left(\neg b \wedge \neg c\right)$$
    Simplificación [src]
    $$a \vee \left(\neg b \wedge \neg c\right)$$ 
    a∨((¬b)∧(¬c))
    Tabla de verdad 
    +---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 1      |
+---+---+---+--------+
| 0 | 0 | 1 | 0      |
+---+---+---+--------+
| 0 | 1 | 0 | 0      |
+---+---+---+--------+
| 0 | 1 | 1 | 0      |
+---+---+---+--------+
| 1 | 0 | 0 | 1      |
+---+---+---+--------+
| 1 | 0 | 1 | 1      |
+---+---+---+--------+
| 1 | 1 | 0 | 1      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    $$a \vee \left(\neg b \wedge \neg c\right)$$ 
    a∨((¬b)∧(¬c))
    FNDP [src]
    $$a \vee \left(\neg b \wedge \neg c\right)$$ 
    a∨((¬b)∧(¬c))
    FNCD [src]
    $$\left(a \vee \neg b\right) \wedge \left(a \vee \neg c\right)$$ 
    (a∨(¬b))∧(a∨(¬c))
    FNC [src]
    $$\left(a \vee \neg b\right) \wedge \left(a \vee \neg c\right)$$ 
    (a∨(¬b))∧(a∨(¬c))
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