Expresión bVc=>a
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
(b∨c)⇒a=a∨(¬b∧¬c)
a∨(¬b∧¬c)
Tabla de verdad
+---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 1 |
+---+---+---+--------+
| 0 | 0 | 1 | 0 |
+---+---+---+--------+
| 0 | 1 | 0 | 0 |
+---+---+---+--------+
| 0 | 1 | 1 | 0 |
+---+---+---+--------+
| 1 | 0 | 0 | 1 |
+---+---+---+--------+
| 1 | 0 | 1 | 1 |
+---+---+---+--------+
| 1 | 1 | 0 | 1 |
+---+---+---+--------+
| 1 | 1 | 1 | 1 |
+---+---+---+--------+
Ya está reducido a FND
a∨(¬b∧¬c)
a∨(¬b∧¬c)
(a∨¬b)∧(a∨¬c)
(a∨¬b)∧(a∨¬c)