Sr Examen

Expresión yv!xzvx!z

El profesor se sorprenderá mucho al ver tu solución correcta😉

    Solución

    Ha introducido [src]
    y∨(x∧(¬z))∨(z∧(¬x))
    $$y \vee \left(x \wedge \neg z\right) \vee \left(z \wedge \neg x\right)$$
    Simplificación [src]
    $$y \vee \left(x \wedge \neg z\right) \vee \left(z \wedge \neg x\right)$$
    y∨(x∧(¬z))∨(z∧(¬x))
    Tabla de verdad
    +---+---+---+--------+
    | x | y | z | result |
    +===+===+===+========+
    | 0 | 0 | 0 | 0      |
    +---+---+---+--------+
    | 0 | 0 | 1 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 0 | 1 | 1 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 0 | 1 | 0      |
    +---+---+---+--------+
    | 1 | 1 | 0 | 1      |
    +---+---+---+--------+
    | 1 | 1 | 1 | 1      |
    +---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    $$y \vee \left(x \wedge \neg z\right) \vee \left(z \wedge \neg x\right)$$
    y∨(x∧(¬z))∨(z∧(¬x))
    FNC [src]
    $$\left(x \vee y \vee z\right) \wedge \left(x \vee y \vee \neg x\right) \wedge \left(y \vee z \vee \neg z\right) \wedge \left(y \vee \neg x \vee \neg z\right)$$
    (x∨y∨z)∧(x∨y∨(¬x))∧(y∨z∨(¬z))∧(y∨(¬x)∨(¬z))
    FNDP [src]
    $$y \vee \left(x \wedge \neg z\right) \vee \left(z \wedge \neg x\right)$$
    y∨(x∧(¬z))∨(z∧(¬x))
    FNCD [src]
    $$\left(x \vee y \vee z\right) \wedge \left(y \vee \neg x \vee \neg z\right)$$
    (x∨y∨z)∧(y∨(¬x)∨(¬z))