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Lógica matemática/ yv!xzvx!z

Expresión yv!xzvx!z

El profesor se sorprenderá mucho al ver tu solución correcta😉

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    Solución

    Ha introducido [src] 
    y∨(x∧(¬z))∨(z∧(¬x))
    $$y \vee \left(x \wedge \neg z\right) \vee \left(z \wedge \neg x\right)$$
    Simplificación [src]
    $$y \vee \left(x \wedge \neg z\right) \vee \left(z \wedge \neg x\right)$$ 
    y∨(x∧(¬z))∨(z∧(¬x))
    Tabla de verdad 
    +---+---+---+--------+
| x | y | z | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 1      |
+---+---+---+--------+
| 0 | 1 | 0 | 1      |
+---+---+---+--------+
| 0 | 1 | 1 | 1      |
+---+---+---+--------+
| 1 | 0 | 0 | 1      |
+---+---+---+--------+
| 1 | 0 | 1 | 0      |
+---+---+---+--------+
| 1 | 1 | 0 | 1      |
+---+---+---+--------+
| 1 | 1 | 1 | 1      |
+---+---+---+--------+
    FND [src]
    Ya está reducido a FND
    $$y \vee \left(x \wedge \neg z\right) \vee \left(z \wedge \neg x\right)$$ 
    y∨(x∧(¬z))∨(z∧(¬x))
    FNC [src]
    $$\left(x \vee y \vee z\right) \wedge \left(x \vee y \vee \neg x\right) \wedge \left(y \vee z \vee \neg z\right) \wedge \left(y \vee \neg x \vee \neg z\right)$$ 
    (x∨y∨z)∧(x∨y∨(¬x))∧(y∨z∨(¬z))∧(y∨(¬x)∨(¬z))
    FNDP [src]
    $$y \vee \left(x \wedge \neg z\right) \vee \left(z \wedge \neg x\right)$$ 
    y∨(x∧(¬z))∨(z∧(¬x))
    FNCD [src]
    $$\left(x \vee y \vee z\right) \wedge \left(y \vee \neg x \vee \neg z\right)$$ 
    (x∨y∨z)∧(y∨(¬x)∨(¬z))
    © Sr Examen