Sr Examen
Expresión ~(~(~(P∨Q))∨~P)∨Q
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Solución
Ha introducido
[src]
q∨(¬((¬p)∨(¬(¬(p∨q)))))
$$q \vee \neg \left(\neg p \vee \neg \left(\neg \left(p \vee q\right)\right)\right)$$
Solución detallada
$$\neg \left(p \vee q\right) = \neg p \wedge \neg q$$
$$\neg \left(\neg \left(p \vee q\right)\right) = p \vee q$$
$$\neg p \vee \neg \left(\neg \left(p \vee q\right)\right) = 1$$
$$\neg \left(\neg p \vee \neg \left(\neg \left(p \vee q\right)\right)\right) = \text{False}$$
$$q \vee \neg \left(\neg p \vee \neg \left(\neg \left(p \vee q\right)\right)\right) = q$$
$$\neg \left(\neg \left(p \vee q\right)\right) = p \vee q$$
$$\neg p \vee \neg \left(\neg \left(p \vee q\right)\right) = 1$$
$$\neg \left(\neg p \vee \neg \left(\neg \left(p \vee q\right)\right)\right) = \text{False}$$
$$q \vee \neg \left(\neg p \vee \neg \left(\neg \left(p \vee q\right)\right)\right) = q$$
Tabla de verdad
+---+---+--------+ | p | q | result | +===+===+========+ | 0 | 0 | 0 | +---+---+--------+ | 0 | 1 | 1 | +---+---+--------+ | 1 | 0 | 0 | +---+---+--------+ | 1 | 1 | 1 | +---+---+--------+