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Lógica matemática/ not(AorB)and(CandB)

Expresión not(AorB)and(CandB)

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    Solución

    Ha introducido [src] 
    b∧c∧(¬(a∨b))
    b∧c∧¬(a∨b)b \wedge c \wedge \neg \left(a \vee b\right)
    Solución detallada
    ¬(a∨b)=¬a∧¬b\neg \left(a \vee b\right) = \neg a \wedge \neg b
    b∧c∧¬(a∨b)=Falseb \wedge c \wedge \neg \left(a \vee b\right) = \text{False}
    Simplificación [src]
    0 
    0
    Tabla de verdad 
    +---+---+---+--------+
| a | b | c | result |
+===+===+===+========+
| 0 | 0 | 0 | 0      |
+---+---+---+--------+
| 0 | 0 | 1 | 0      |
+---+---+---+--------+
| 0 | 1 | 0 | 0      |
+---+---+---+--------+
| 0 | 1 | 1 | 0      |
+---+---+---+--------+
| 1 | 0 | 0 | 0      |
+---+---+---+--------+
| 1 | 0 | 1 | 0      |
+---+---+---+--------+
| 1 | 1 | 0 | 0      |
+---+---+---+--------+
| 1 | 1 | 1 | 0      |
+---+---+---+--------+
    FNCD [src]
    0 
    0
    FND [src]
    Ya está reducido a FND
    0 
    0
    FNC [src]
    Ya está reducido a FNC
    0 
    0
    FNDP [src]
    0 
    0
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