Sr Examen
Expresión (~P→Q)∧(Q↔P)
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Solución detallada
$$p ⇔ q = \left(p \wedge q\right) \vee \left(\neg p \wedge \neg q\right)$$
$$\neg p \Rightarrow q = p \vee q$$
$$\left(p ⇔ q\right) \wedge \left(\neg p \Rightarrow q\right) = p \wedge q$$
$$\neg p \Rightarrow q = p \vee q$$
$$\left(p ⇔ q\right) \wedge \left(\neg p \Rightarrow q\right) = p \wedge q$$
Tabla de verdad
+---+---+--------+ | p | q | result | +===+===+========+ | 0 | 0 | 0 | +---+---+--------+ | 0 | 1 | 0 | +---+---+--------+ | 1 | 0 | 0 | +---+---+--------+ | 1 | 1 | 1 | +---+---+--------+